, c=2

This is what I did:

Now, what do I do next since its centered at c=2??

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- April 11th 2009, 04:01 PMsaiyanmx89Find the power series representation of this function
, c=2

This is what I did:

Now, what do I do next since its centered at c=2?? - April 11th 2009, 04:05 PMJhevon
- April 11th 2009, 04:11 PMsaiyanmx89
???

- April 11th 2009, 04:17 PMJhevon
- April 11th 2009, 04:29 PMsaiyanmx89
(-3)(x-2)^n ?

- April 11th 2009, 04:44 PMJhevon
question: what form for the power series are you trying to use? you are trying to use the fact that , for , am i right?

now look at what we have. does it look like it is in that form? is the constant in the denominator a 1? is it 1 - (some function of x) in the denominator? no it isn't. get it into that form before you make the power series - April 11th 2009, 04:51 PMsaiyanmx89
Could this work:

But the -3 still needs to be taken out right?? - April 11th 2009, 04:56 PMJhevon
- April 11th 2009, 05:09 PMsaiyanmx89
I'm sorry for asking such a mundane question but, how would I take out the (1/3)?

- April 11th 2009, 05:14 PMJhevon
- April 12th 2009, 09:51 AMsaiyanmx89
Why is this form acceptable then for c=0??

, c=0

I understand that is the same thing, but is this just something you have to do when the function isn't centered at 0? - April 12th 2009, 10:46 AMJhevon
if c = 0 it means you want your function part to look like (x - 0) which happens to just be x. thus, having that x there (possibly times some constant) is good enough. then, you have the constant in front being a "+1", so we have the form. you would NOT change it to 4 - 3 - 2x, because that is getting away from the form you want, which is , where is some function in . in general, you would want in this case,