It is easier to solve the 2nd derivative than you may think at first glance.
Concentrate on the numerator. e is never 0, so all we have to do is solve
, x=1, x=-1
I know to find inflection points you need to compute the 2nd derivative test and set equal to 0. I think I got the 2nd derivative but I'm lost on the rest. Here is the problem with 1st and 2nd derivatives computed:
Problem #1 -
f(x) = e^(-x^2/2) / sqrt[2*pi]
f'(x) = -e^(-x^2/2) / sqrt[2*pi]
f"(x) = e^(-x^2/2) (x^2-1) / sqrt[2*pi]
I have another problem to find inflection pts. No idea where to start:
Problem #2 -
g(x) = e^[(-(x-a)^2)/(2b^2)] / sqrt[2*pi*b^2]
Can anyone help?? These are tough problems!!