# Thread: find Amperes per second

1. ## find Amperes per second

In a simple electric circuit, Ohm's law states that , where V is the voltage in volts, I is the current in amperes, and R is the resistance in ohms. Assume that, as the battery wears out, the voltage decreases at 0.01 volts per second and, as the resistor heats up, the resistance is increasing at 0.04 ohms per second. When the resistance is 300 ohms and the current is 0.01 amperes, at what rate is the current changing?
___________amperes per second

hey guys, i am hard time setting up this problem, plz help, i know we gonna have to use chain rule but how?

2. Originally Posted by DMDil
In a simple electric circuit, Ohm's law states that , where V is the voltage in volts, I is the current in amperes, and R is the resistance in ohms. Assume that, as the battery wears out, the voltage decreases at 0.01 volts per second and, as the resistor heats up, the resistance is increasing at 0.04 ohms per second. When the resistance is 300 ohms and the current is 0.01 amperes, at what rate is the current changing?
___________amperes per second

hey guys, i am hard time setting up this problem, plz help, i know we gonna have to use chain rule but how?
Product rule: $\frac{dV}{dt} = I \frac{dR}{dt} + R \frac{dI}{dt}$.

Substitute the given data and solve for $\frac{dI}{dt}$.

3. Thanks alot, this thing have started to make some sense now..