Set up a graph for the derivative -sin(x) -cos(x) on (-pi,pi)
you already know the zeroes--so just look where the graph is positive
If you must use a table consider -pi to pi/4, -pi/4 to 3pi/4 and 3pi/4 to pi
interval -pi<=x<=pi
y=cosx-sinx
dy/dx= -sinx-cosx
sinx=-cosx
cosx=-sinx
tanx=-1
two angles are -pi/4 and 3pi/4
I am stuck here. Normally i would use a table to determine the period of increase and decrease from y'. How do you set up the table in this case?
[-pi ............-pi/4..............3pi/4.............pi]
pick a value in each interval, and determine the sign of y' in that interval.
first interval, y'(-pi) > 0 ... y is increasing
second interval, y'(0) < 0 ... y is decreasing
third interval, y'(pi) > 0 ... y is increasing