f(x) = (x^2)cosx f'(x) = 2xcosx - (x^2)sinx f''(x) = 2cosx - 4xsinx - (x^2)cosx Did I do the second derivative right?
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Originally Posted by saiyanmx89 f(x) = (x^2)cosx f'(x) = 2xcosx - (x^2)sinx f''(x) = 2cosx - 4xsinx - (x^2)cosx Did I do the second derivative right? yup
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