Differentiate the equation and get the value of y' in terms of "x"

1)Find value of y'(-2) by putting x = -2

2)

at x = -2 , y=?

the equation of tangent can be given by

y= mx+c

this euation should satisfy the for the point (-2,?)

, you know the value of m [it is, y'(-2) ]

use this two facts to find "c"

Hence equation is with you