what is the derivative of -3/x^2 + 3lnx - 6e^x
thank you for your help
Your formatting is ambiguous. I think the other replies have assumed that you meant the following:
. . . . .$\displaystyle -\frac{3}{x^2}\, +\, 3\ln(x)\, -\, 6e^x$
Is the above what you meant? Or did you mean "-3/(x^2 + 3ln(x) - 6e^x)", which, in LaTeX, looks like the following?
. . . . .$\displaystyle \frac{-3}{x^2\, +\, 3\ln(x)\, -\, 6e^x}$
When you reply, please show what you have tried so far, so we can "see" which part is causing confusion. Thank you!