That is exactly what I did.

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- Dec 7th 2006, 08:22 AMThePerfectHacker
- Dec 7th 2006, 08:55 AMCaptainBlack
- Dec 7th 2006, 09:14 AMtotalnewbie
$\displaystyle \int\frac{dx}{x\sqrt{x^2-1}}$

using substitution $\displaystyle x=\frac{1}{t}$ in order to find integral

i got that $\displaystyle dx=-\frac{dt}{t^2}$

if i substitute it what should i do with denominator, especially with sqrt ?

oh i hate it. i am going to have a test tomorrow - Dec 7th 2006, 03:26 PMJameson
Please post new questions in new threads.