$\displaystyle \int{\frac{\sqrt{x}-x^2+4}{x}}dx$
Lost on what to do.
Thanks for the help!
$\displaystyle \int{\frac{\sqrt{x}-x^2+4}{x}}dx$
$\displaystyle \int (\frac{1}{\sqrt{x}} - x + \frac{4}{x}) dx$
$\displaystyle \int (-x^{1/2}-x+\frac{4}{x}) dx$
Would that be the correct step, i'm lost after that. Not sure how to get the antiderivatives to evaluate
Since this answer means you have done the integral, the integration operator should not be included. So you have
$\displaystyle \frac{-x^{3/2}}{3/2} - \frac{x^2}{2} + \int \! \frac{4}{x} \, dx$.
The last integral is equal to $\displaystyle 4 \ln |x | $ (again, you're expected to know this.)
Your final answer needs to include a "+ C" (and again, this is something you're meant to know).