I can not seem to get the correct answer on the following integral.
Integral from (1-x) up to 2 of (2x+2-y)/(4) dy
Please show the steps so i can see what I am doing wrong. Thanks
$\displaystyle \frac{1}{4}\int_0^1 \int 2x+2-y \,dy\,dx = \frac{1}{4} \int_0^1 2(x+1)y - \left. \frac{y^2}{2} \right|_{1-x}^2 dx $
$\displaystyle = \frac{1}{4} \int_0^1 \left( 4(x+1) - 2\right) - \left( 2(1+x)(1-x) - \frac{(1-x)^2}{2}\right)dx = \frac{1}{8}\int_0^1 5x^2 + 6x + 1\,dx$
Did you get this?