Find the equation of the curve for whichy''=10 if the curve is tangent to the liney = 13xat (2, 26).

like give me the steps on how to solve it ...

i think im suppose to

1. integrate y''= 10 and get y = 5 x ^2 +c

2. sub in (2,26) and solve for c and get c = 6

i dont really know what to do after this ... i missed the lecture on it and my test is on the monday and theres no one i can really ask for help