Can someone check to see if I evaluated this correctly? Is that right?
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Originally Posted by mollymcf2009 Can someone check to see if I evaluated this correctly? Is that right? no (9n - 1)! = (9n - 1)(9n - 2)(9n - 3)....(3)(2)(1)
Originally Posted by Jhevon no (9n - 1)! = (9n - 1)(9n - 2)(9n - 3)....(3)(2)(1) Ok, I need a hint....
Originally Posted by Jhevon no (9n - 1)! = (9n - 1)(9n - 2)(9n - 3)....(3)(2)(1) Ok, how about...9n!-1
Originally Posted by mollymcf2009 Ok, how about...9n!-1 It doesn't work for values of !! XD What in particular are you asked to do with this series? Show that it converges??
Originally Posted by Chris L T521 It doesn't work for values of !! XD What in particular are you asked to do with this series? Show that it converges?? Find the radius of convergence and the interval of convergence. I don't know a good way to rewrite factorials. Do I need to do that before I try to evaluate this? Thanks Chris!
Originally Posted by mollymcf2009 Find the radius of convergence and the interval of convergence. I don't know a good way to rewrite factorials. Do I need to do that before I try to evaluate this? Thanks Chris! if that's the case, why not use the ratio or root test? you don't need to rewrite anything. probably the ratio test will be easier here however, in general, you can use Stirling's approximation.
Do you mean n=1 instead of n+1?
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