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Math Help - Solving This Variable confuse me

  1. #1
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    Solving This Variable confuse me

    Solving this for Theta confuses the heck out of me and its a rather simple equation

    (1-2u\theta-\theta^2)
    Last edited by mr fantastic; April 9th 2009 at 03:29 AM. Reason: ll --> ck
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  2. #2
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    e^(i*pi)'s Avatar
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    Quote Originally Posted by sk8erboyla2004 View Post
    Solving this for Theta confuses the hell out of me and its a rather simple equation

    (1-2u\theta-\theta^2)
    You need it to be equal to something to solve as an equation. If it is equal to 0 use the quadratic formula with a= -1, b = -2u and c =1
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  3. #3
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    Yes it is equal to 0
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    Quote Originally Posted by sk8erboyla2004 View Post
    Yes it is equal to 0
    You can use the quadratic formula to solve this.

    -\theta^2 - 2u\theta +1 = 0

    compare to ax^2+bx+c = 0

    I get an answer of \theta = -u\pm \sqrt{u^2+1}
    Last edited by e^(i*pi); April 8th 2009 at 06:53 PM. Reason: oops forgot the minus sign
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  5. #5
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    I get

    \frac{2u\pm\sqrt{2u^2-4}}{-2}


    Im confused how to simplfy


    I can see how to reduce too



    {-u\pm\sqrt{u^2-2}}
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  6. #6
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    Quote Originally Posted by sk8erboyla2004 View Post
    I get

    \frac{2u\pm\sqrt{{\color{red}(-}2u{\color{red})}^2-4{\color{red}(-1)(1)}}}{-2}


    Im confused how to simplfy


    I can see how to reduce too



    {-u\pm\sqrt{u^2-2}}
    You need to take more care. See my above edits in red and continue.
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  7. #7
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    Quote Originally Posted by sk8erboyla2004 View Post
    I get

    \frac{2u\pm\sqrt{2u^2-4}}{-2}


    Im confused how to simplfy


    I can see how to reduce too



    {-u\pm\sqrt{u^2-2}}

    {-u\pm\sqrt{u^2+2}}
    Last edited by mr fantastic; April 9th 2009 at 04:46 AM. Reason: Fixed latex
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  8. #8
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    Quote Originally Posted by sk8erboyla2004 View Post
    {-u\pm\sqrt{u^2+2}}
    No. Show your working. (The correct answer is given in post #4).
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