remember any integral from 0 to 0 or in fact a to a is 0.
No one can do the integral
I am trying to get the first four terms of the Maclaurin Series for the following functiong:
integral from 0 to x of sqrt(1+t^3) dt
Sadly, I'm stuck trying to find the integral so that I can get the first f(0) term. Using u-substitution I get:
u = 1 + t^3
du = 3t^2 dt
dt= du / 3t^2
I think that I need to put 3t^2 in terms of u to be able to continue with the integration, but I cannot see a connection. If I make u = t^3 then would 3t^2 = 3u^2/3 ??
thanks!