# Math Help - Quick Help Realizing This simplification

1. ## Quick Help Realizing This simplification

I got this when Im suppose to be solving for x

$b(\frac{-2a^2}{x^3}-\frac{a}{x^2})=0$

but i dont see how it can me turned into this -its from an example the book

$-2a^2+ax=0$

2. Originally Posted by sk8erboyla2004
I got this when Im suppose to be solving for x

$b(\frac{-2a^2}{x^3}-\frac{a}{x^2})=0$

but i dont see how it can me turned into this -its from an example the book

$-2a^2+ax=0$
$b\left(\frac{-2a^2}{x^3}-\frac{a}{x^2}\right)=0\implies b\left(\frac{-2a^2}{x^3}-\frac{ax}{x^3}\right)=0$ $\implies b\left(\frac{-2a^2-ax}{x^3}\right)=0\implies -2a^2-ax=0$

I'm not sure where its getting $-2a^2{\color{red}+}ax=0$, unless there is a typo somewhere in what you posted.

3. nah, there is a plus in the manual unless they distributed the minus in front the -2a^2