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Math Help - Position of function at Rest

  1. #1
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    Position of function at Rest

    Post of a function is s = t^3 - 6t^2 + 9t + 1

    When is the particle at rest?

    Can someone do a step by step for me...I have a test soon so I kinda just need to know.
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  2. #2
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    Quote Originally Posted by Dickson View Post
    Post of a function is s = t^3 - 6t^2 + 9t + 1

    When is the particle at rest?

    Can someone do a step by step for me...I have a test soon so I kinda just need to know.
    The particle is at rest when the velocity is 0.

    v = \frac{ds}{dt} = 3t^2 - 12t + 9

    0 = 3t^2 - 12t + 9

    0 = 3t^2 - 9t - 3t + 9

    0 = 3t(t - 3) - 3(t - 3)

    0 = (t - 3)(3t - 3)

    The particle is at rest at t = \{1, 3\}.
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    Thanks a lot
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