Integration using partial fraction-Irreducible Quadratic Factor 1

**sanikui** · April 6th 2009, 11:48 PM

Integrate x^3 + 4x^2 + 9x + 14
.................x^2 + 4x + 3

**chisigma** · April 7th 2009, 01:10 AM

The function can be decomposed in partial fractions as follows...

$f(x)= \frac{x^{3}+ 4\cdot x^{2} + 9\cdot x + 14}{x^{2} + 4\cdot x + 3}= x + \frac {6\cdot x + 14}{x^{2} + 4\cdot x + 3}= x + \frac{a}{x+3} + \frac{b}{x+1}$

The constants a and b are easily found, after that f(*) can be integrated in 'standard fashion'...

Kind regards

$\chi$ $\sigma$

**sanikui** · April 7th 2009, 05:05 AM

i get it.
Thanks.

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