# Integration using partial fraction-Irreducible Quadratic Factor 1

• Apr 6th 2009, 11:48 PM
sanikui
Integration using partial fraction-Irreducible Quadratic Factor 1
Integrate x^3 + 4x^2 + 9x + 14
.................x^2 + 4x + 3
• Apr 7th 2009, 01:10 AM
chisigma
The function can be decomposed in partial fractions as follows...

$f(x)= \frac{x^{3}+ 4\cdot x^{2} + 9\cdot x + 14}{x^{2} + 4\cdot x + 3}= x + \frac {6\cdot x + 14}{x^{2} + 4\cdot x + 3}= x + \frac{a}{x+3} + \frac{b}{x+1}$

The constants a and b are easily found, after that f(*) can be integrated in 'standard fashion'...

Kind regards

$\chi$ $\sigma$
• Apr 7th 2009, 05:05 AM
sanikui
i get it.
Thanks.