Integratex^3 + 4x^2 + 9x + 14

.................x^2 + 4x + 3

- Apr 6th 2009, 11:48 PMsanikuiIntegration using partial fraction-Irreducible Quadratic Factor 1
Integrate

__x^3 + 4x^2 + 9x + 14__

.................x^2 + 4x + 3 - Apr 7th 2009, 01:10 AMchisigma
The function can be decomposed in partial fractions as follows...

$\displaystyle f(x)= \frac{x^{3}+ 4\cdot x^{2} + 9\cdot x + 14}{x^{2} + 4\cdot x + 3}= x + \frac {6\cdot x + 14}{x^{2} + 4\cdot x + 3}= x + \frac{a}{x+3} + \frac{b}{x+1}$

The constants a and b are easily found, after that f(*) can be integrated in 'standard fashion'...

Kind regards

$\displaystyle \chi$ $\displaystyle \sigma$ - Apr 7th 2009, 05:05 AMsanikui
i get it.

Thanks.