I'm blanking out on this one.. integral from -1 to 3 of.. sq.root(1 + (2x-5)^2) Don't need you guys to do it, just give me a hint on how to go about it.. this is probably easy, I'm just blanking out
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Originally Posted by coolguy99 I'm blanking out on this one.. integral from -1 to 3 of.. sq.root(1 + (2x-5)^2) Don't need you guys to do it, just give me a hint on how to go about it.. this is probably easy, I'm just blanking out let $\displaystyle 2x-5=\tan(\theta) \implies 2dx=\sec^{2}(\theta)d\theta$
Originally Posted by coolguy99 I'm blanking out on this one.. integral from -1 to 3 of.. sq.root(1 + (2x-5)^2) Don't need you guys to do it, just give me a hint on how to go about it.. this is probably easy, I'm just blanking out Let $\displaystyle 2x-5=\tan\theta$. It should be straightforward from there.
Originally Posted by coolguy99 I'm blanking out on this one.. integral from -1 to 3 of.. sq.root(1 + (2x-5)^2) Don't need you guys to do it, just give me a hint on how to go about it.. this is probably easy, I'm just blanking out $\displaystyle \int_{-1}^3\sqrt{1+(2x-5)^2}\,dx$ Substitute $\displaystyle 2x-5=\tan\theta\Rightarrow dx=\frac12\sec^2\theta\,d\theta.$ Edit: Curses! I've been beaten!
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