Evaluate the following indefinite integrals: $\displaystyle \int{(5x^2-6x+3)}dx$ Thanks for any help!
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Originally Posted by Jim Marnell Evaluate the following indefinite integrals: $\displaystyle \int{(5x^2-6x+3)}dx$ Thanks for any help! $\displaystyle \int ax^{n} dx = \frac{ax^{n+1}}{n+1} + C $ That's all you need to know for this.
your answer came up as an error, might have typed something wrong
Originally Posted by Jim Marnell your answer came up as an error, might have typed something wrong I have corrected it.
Thanks 4 the help!
$\displaystyle \int{(5x^2-6x+3)}dx$ $\displaystyle 5\int{x^2dx}-(6\int{xdx})+(3\int{dx})$ $\displaystyle 5(\frac{x^3}{3})-6(\frac{x^2}{2})+3x+c$ $\displaystyle \frac{5}{3}x^3-3x^2+3x+c$
Originally Posted by Jim Marnell $\displaystyle \int{(5x^2-6x+3)}dx$ $\displaystyle 5\int{x^2dx}-(6\int{xdx})+(3\int{dx})$ $\displaystyle 5(\frac{x^3}{3})-6(\frac{x^2}{2})+3x+c$ $\displaystyle \frac{5}{3}x^3-3x^2+3x+c$
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