# Indefinite Integrals

• Apr 6th 2009, 06:29 PM
Jim Marnell
Indefinite Integrals
Evaluate the following indefinite integrals:

$\displaystyle \int{(5x^2-6x+3)}dx$

Thanks for any help!
• Apr 6th 2009, 06:37 PM
Mush
Quote:

Originally Posted by Jim Marnell
Evaluate the following indefinite integrals:

$\displaystyle \int{(5x^2-6x+3)}dx$

Thanks for any help!

$\displaystyle \int ax^{n} dx = \frac{ax^{n+1}}{n+1} + C$

That's all you need to know for this.
• Apr 6th 2009, 06:40 PM
Jim Marnell
your answer came up as an error, might have typed something wrong
• Apr 6th 2009, 06:42 PM
Mush
Quote:

Originally Posted by Jim Marnell
your answer came up as an error, might have typed something wrong

I have corrected it.
• Apr 6th 2009, 06:44 PM
Jim Marnell
Thanks 4 the help!
• Apr 6th 2009, 07:02 PM
Jim Marnell
Is this right?
$\displaystyle \int{(5x^2-6x+3)}dx$
$\displaystyle 5\int{x^2dx}-(6\int{xdx})+(3\int{dx})$
$\displaystyle 5(\frac{x^3}{3})-6(\frac{x^2}{2})+3x+c$
$\displaystyle \frac{5}{3}x^3-3x^2+3x+c$
• Apr 6th 2009, 07:05 PM
Chris L T521
Quote:

Originally Posted by Jim Marnell
$\displaystyle \int{(5x^2-6x+3)}dx$
$\displaystyle 5\int{x^2dx}-(6\int{xdx})+(3\int{dx})$
$\displaystyle 5(\frac{x^3}{3})-6(\frac{x^2}{2})+3x+c$
$\displaystyle \frac{5}{3}x^3-3x^2+3x+c$

(Yes)