so factoring the bottom we get
so we have
A / x-1
B / x+6
now what? I know you have to do this
x+4 = A(x+6) + B(x-1)(x+6)/(x-6)
now im stuck because of the x-6 in denominator
All I meant with "by design" was that the denominator will always cancel because of the way partial fractions work.
Those values for a and b are correct.
This is as you say du/u which integrates to ln(u).
So we have which is what you have I hope?
The following are true for logs: