$\displaystyle

\int\frac{x+4}{x^2+5x-6}\,dx

$

so factoring the bottom we get

$\displaystyle

\int\frac{x+4}{(x-1)(x+6)}\,dx

$

so we have

A / x-1

B / x+6

now what? I know you have to do this

x+4 = A(x+6) + B(x-1)(x+6)/(x-6)

now im stuck because of the x-6 in denominator