integrate e^-xdx over the interval [0,1]

let u=?

du= ?

when x= 0, u=?

when x = 1, u = ?

thanks!

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- Apr 5th 2009, 07:01 AMLexiRaehelp with integrating e^-x over the interval [0,1]
integrate e^-xdx over the interval [0,1]

let u=?

du= ?

when x= 0, u=?

when x = 1, u = ?

thanks! - Apr 5th 2009, 07:18 AMred_dog

- Apr 5th 2009, 07:22 AMScott H
First, you may note that , and therefore that by the Chain Rule.

When and , we want the derivative to end up with the positive coefficient instead of . To do this, we add a as a coefficient to the antiderivative so that we will end up with :

The general antiderivative is therefore .

Alternatively, we could let

to obtain