Hi there...

Okay, so... I'm trying to find out why...

Integral of 1 / (1 + k * x) dx

[1] results in (from Maple)... ln(1 + k * x)/k?

I've tried to use substitution (with help from Maple), which leads to...

u = 1/k + x

du = 1

What I suppose would lead to the following...

Integral of 1 / (k * u) du

[2] = LN| (1/k) + x | * (1/k)

Now... [1] and [2] are not similar... Can anyone explain what I'm not doing right?

Thanks

Simon DK