I'm trying to find the general formula for the derivative of sqrt(x). I have the x^(1/2-1) part by I can't figure out the formula for the coefficient. Can anyone help me? I know it goes 1/2, -1/4, 3/8, -15/16.....i just cant figure out the formula.

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- Apr 3rd 2009, 07:42 PMhayter221General formula of derivative
I'm trying to find the general formula for the derivative of sqrt(x). I have the x^(1/2-1) part by I can't figure out the formula for the coefficient. Can anyone help me? I know it goes 1/2, -1/4, 3/8, -15/16.....i just cant figure out the formula.

- Apr 3rd 2009, 08:32 PMmatheagle
are you asking for the $\displaystyle n^{th}$ derivative of $\displaystyle \sqrt{x}$?

- Apr 4th 2009, 05:40 AMhayter221
yes.