Thread: a horizontal asymptote problem .. help please

okay so I know that you get the horizontal asymptote when you allow the variable to approach infiniti and basically just look at the degrees and coefficients.. but I'm not sure about this.
my problem says:
f(x) = sin (x+1 / x^2)
theres a vertical asymptote at zero..
is the horizontal asymptote at 0 as well?

It should be, because the exponent in denominator is larger then numerator.

Originally Posted by breezie_93

f(x) = sin (x+1 / x^2)
theres a vertical asymptote at zero..
is the horizontal asymptote at 0 as well?

Is the argument of the sine is meant to be , or does the formatting in the quote above accurately reflect an argument of ? (The answer will vary, accordingly.)

Thank you!