It should be, because the exponent in denominator is larger then numerator.
okay so I know that you get the horizontal asymptote when you allow the variable to approach infiniti and basically just look at the degrees and coefficients.. but I'm not sure about this.
my problem says:
f(x) = sin (x+1 / x^2)
theres a vertical asymptote at zero..
is the horizontal asymptote at 0 as well?