if F(x) = sin^5 (x/6) + cos^4 (x/3)
I'm doing the wrong derivative, i thought that the derivative of
sin(x/6) = cos (x/6)
but that doesn't seem to be correct.
Let's say we're looking at
(sin(x/6))^5 ( i took the 5 out for chain rule purposes)
5(sin(x/6))^4 is the derivative of the outside applied to the inside,
and the derivative of the inside(sin(x/6)) is x/6 * (cos(x/6))??
i thought that the derivative would be
5(sin(x/6))^4 * (cos(x/6))
is there a rule for the x/6 to come out of there?
I can solve the problem, i just need to figure out if i'm missing something specifically with the derivative.
i can't exactly keep going if the derivative is wrong
thanks a bunch