y = x(ln x)^3
How do you sketch this? is there any asymptotes? intercepts? min/max value? Any help will be greatly appreciated!
Well, the graph of just y=ln(x) just keeps growing on for infinity, and so does the graph of y=x, so combining those two together, you can pretty much guarantee that the graph is going to still grow on to infinity.
You also know that the ln(1) = 0, so the function will equal 0 at x=1.
and because you can't take the ln of a negative number, you know there's a vertical asymptote at x=0