Hi everyone, I'm trying the find the zeros of the derivative 4x^3 + 9x^2 + 6x +1 so I set it to zero but I am stuck as to how I can factor this. btw the original function is x*(x+1)^2
I've asked a tutor at my school's tutoring center and she said that I should use my calc to find the zeros, which visually look like 1 and ~-2.5.
Any help would be much appreciated!
I don't see where fits in .... is this another function for which you have to find the zeros of its derivative? Again, the derivative is a quadratic. and there is no trouble.
Or are you trying to solve in which case you note that by inspection is a solution. Therefore is a factor. Divide the factor into the cubic to get . Now solve .