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Math Help - Calculus - kinematics

  1. #1
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    Calculus - kinematics

    Hi, i have a question regarding kinematics.

    I know that acceleration is the rate of change of velocity.
    and if a<0, it is known as deceleration.

    Consider a particle moving in a straight line and the velocity is given by
    v(t)=1-t, a simple linear function,

    For 0<t<1, acceleration is -ve so the particle is decelerating.

    At t=1, v=0, so the particle is at rest.

    Then for t>1, the particle change direction and increases its speed.

    However, for t>1, acceleration, dv/dt is still -ve, but it is not decelerating for t>1 right? It should be accelerating!

    Can anyone correct my concept?? I m quite confused about this part.

    Thanks!!
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    can I say that for the reverse direction, negative acceleration actually means the speed is increasing, whereby positive acceleration means deceleration?
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    Quote Originally Posted by acc100jt View Post
    can I say that for the reverse direction, negative acceleration actually means the speed is increasing, whereby positive acceleration means deceleration?
    You have to define the positive and negative direction. Then:

    If the object is moving in the positive direction and has negative acceleration then it will be slowing down.

    If the object is moving in the negative direction and has positive acceleration then it will be slowing down.

    If the object is moving in the positive direction and has positive acceleration then it will be speeding up.

    If the object is moving in the negative direction and has negative acceleration then it will be speeding up.
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