Find the volume of the solid above the cone $\displaystyle z=\sqrt{x^2+y^2}$ and below the sphere $\displaystyle x^2+y^2+z^2=1$

Obviously use polar coordinates here.

So the two equations are $\displaystyle z=r$ and $\displaystyle z=\sqrt{1-r^2}$.

I'm trying to draw the region of integration in the x-y plane and getting stuck. I think the cone comes down to a single point at (0,0), so maybe that can be disregarded. The sphere has a projection of a unit circle. So is the region of integration the unit circle?

Also what are the bounds for the integral?