Hello, first time posting on this forum, but definitely not the first time I've followed it. I was hoping someone could help me with this surface area problem:

Find the area of the surface obtained by rotating the curve $\displaystyle y=sqrt(2x)$ about the x-axis from x=0 to x=5. sqrt meaning square root obviously.

from my own troubled math, I'm coming up with a wrong answer of

$\displaystyle (2/3)*pi*(2x)^ (3/2) = 66.2306$

sorry for the bad character illustration, thats supposed to be 2x to the 3/2 power.

I believe my source of error is in the beginning because I do not think I am getting out of the initial Surface Area square root formula properly.