Just need a line by line for how to find the derivative of -
6(2x-9)^5 and x^-4+(x^3-4)^-2/5 thanks
6(2x-9)^5
Alright, you have the chain rule here, so..
the exponent comes down, the polynomial's exponent is subtracted by 1, and you take the inside of the parenthesis' derivative and multiply it
5(6(2x-9)^4) (2)
everything else remains unchanged.
x^-4 is the same principle as up above. think of it as (x)^(-4)
(x^3-4)^-2/5
the exponent comes down, polynomial's exponent is subtracted by 1, and you take the inside of the parenthesis' derivative and multiply it
(-2/5)(x^3-4)^(-7/5)[(3x^2)]