i for the x and y value but i need help finding the slope. the equation is f(x) = tanx at x=pi/4 i know the derivative of this is sec^2(x) so y = sec^2(pi/4) i dont know how to get the value of this
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Originally Posted by proski117 i for the x and y value but i need help finding the slope. the equation is f(x) = tanx at x=pi/4 i know the derivative of this is sec^2(x) so y = sec^2(pi/4) i dont know how to get the value of this $\displaystyle \frac{\pi}{4}$ is on the standard triangle. $\displaystyle sec^2(x) = \frac{1}{cos^2(x)}$ As $\displaystyle cos{\frac{\pi}{4}} = \frac{\sqrt(2)}{2}$ so $\displaystyle cos^2{\frac{\pi}{4}} = \frac{1}{2}$ therefore $\displaystyle cos^2{\frac{\pi}{4}} = 2$
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