Coffee is draining from a conical filter into a cylindrical coffeepot at the rate of 5 cubic centimeters per minute. The conical filter measures 10 cm tall and 10 cm across its top. The diameter of the coffeepot is 10 cm.

How fast is the level of coffee in the pot rising when the level in the filter is 8 cm deep? Remember...the diameter of the coffeepot is 15 cm.

dV/dt= +10 cm^3/min

V=TTr^2h

r is a constant

V=TT(7.5)^2h

I know I have to take the time derivative and solve for dh/dt, but I can't figure it out...