Got a taylor series question here, just want to see if I'm on the right track
f(x) = x^(-1/2) at a = 9
Took the derivative a bunch..
f'(x) = (-1/2)x^-(3/2)
f''(x) = (-1/2)(-3/2)x^-(5/2)
f'''(x) = (-1/2)(-3/2)(-5/2)x^-(7/2)
f4(f) = (-1/2)(-3/2)(-5/2)(-7/2)x^-(9/2)
so the taylor series at a = 9 would be..
[(-1)^n][(x-9)^(-1/2 - n)][2n-1]/[(n!)(2^n)]
or am I way off?