$\displaystyle \int\frac{x^2}{1+({2x})^2} dx$

I know that the bottom is going to end up being

$\displaystyle \arctan{2x}$

but how do I get rid of the $\displaystyle x^2$

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- Mar 30th 2009, 09:49 PMsummermagicLast Integration Problem...I Swear!
$\displaystyle \int\frac{x^2}{1+({2x})^2} dx$

I know that the bottom is going to end up being

$\displaystyle \arctan{2x}$

but how do I get rid of the $\displaystyle x^2$ - Mar 30th 2009, 09:54 PMmatheagle