Take a look at the first pattern. The denominator is 2 plus the numerator for all terms. Therefore, if the numerator is j, the denominator is j+2. So, the first summations is:

SIGMA_(j=3 to 7)_[j/(j+2)].

The second pattern emphasizes a sign change. This is always achieved with (-1)^n, so that if n is odd, the sign is minus (why?) and if n is even, the sign is plus. The first term is 1, or a^0, so it is convenient to start the summation from zero:

SIGMA_(j=0 to n)_[(-1)^j*(a^j)].