The question reads: Evaluate the area of the region bounded by y=sec^2x and y = 4 between x = -pi/3 and x = pi/3. Thank You!
Follow Math Help Forum on Facebook and Google+
Originally Posted by Meeklo Braca The question reads: Evaluate the area of the region bounded by y=sec^2x and y = 4 between x = -pi/3 and x = pi/3. Thank You! sketch the graph and you will see that y=4 is the upper curve so we get.. Just integrate from here
Originally Posted by Meeklo Braca The question reads: Evaluate the area of the region bounded by y=sec^2x and y = 4 between x = -pi/3 and x = pi/3. Thank You! integrate and evaluate.
I dont know how to integrate that
Originally Posted by Meeklo Braca I dont know how to integrate that what exactly is it that you don't know? don't know the antiderivatives of and ? don't know how to use the fundamental theorem of calculus?
i dont know the anti derivative of sec^2x
Originally Posted by Meeklo Braca i dont know the anti derivative of sec^2x what is the derivative of ?
I gotcha, So I have A = x^2 -tan x, Where do I go from there?
Originally Posted by Meeklo Braca I gotcha, So I have A = x^2 -tan x, Where do I go from there? that is incorrect ... the antiderivative of is . last step is to evaluate the definite integral using the fundamental theorem of calculus.
I know the fundamental theorm of calculus for non trig functions. The trig throws me for a loop. What form should my answer be in?
Originally Posted by Meeklo Braca I know the fundamental theorm of calculus for non trig functions. The trig throws me for a loop. What form should my answer be in? The fundemental theorem of calculus is the same for trig functions.... Just evaluate the antiderivative at the end points and subtract.
What form should my final answer be? If I calculate it out its 4.81 but I have a feeling thats not the correct answer.
Originally Posted by Meeklo Braca What form should my final answer be? If I calculate it out its 4.81 but I have a feeling thats not the correct answer.
OK I will go with that. Thank you very much for your help and insight!
View Tag Cloud