Given the function:
My book says:
I'm pretty sure this is a utilization of the chain rule, but I don't really understand it, can someone clear it up for me?
(ps, sorry I could not get it to show up any clearer...)
chain rule is g'(h(x)) h'(x) . which means..
g(x)=sin(x) [x being sin(2Pi)]
g'(x)=cos(x)
h(x)=sin(2Pi) and
h'(x)=0 .
put it all into the function and you get..
cos(sin(2Pi)) (0)
which ends up giving you a 0 anyways. are you sure thats what the book is saying? lol i mean it sounds dumb to ask but this is the way i did it.. idk and i tried many times on the calculator and i keep getting zero because the derivative of t is 1.. and anything that you multiply by zero stays zero... you know??? any more info you have?