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  1. #1
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    differentiate


    1. Differentiate the following with respect to x
    a.
    y=3/2x2
    b.
    y=ln (x3+x)
    c.
    y=ex/1n(3x)

    can anyone manage this? good luckxx
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  2. #2
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    Quote Originally Posted by snappy23 View Post

    1. Differentiate the following with respect to x
    a. y=3/2x2
    b. y=ln (x3+x)
    c. y=ex/1n(3x)

    can anyone manage this? good luckxx
    1. I'm assuming the function is y = \frac{3}{2x^2}

    rewrite as y = \frac{3}{2}x^{-2} ... now use the power rule for derivatives.

    2. derivative for the log of a function y = \ln(u) ...

    y' = \frac{u'}{u}

    3. y = \frac{e^x}{\ln(3x)} ... use the quotient rule
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  3. #3
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    Quote Originally Posted by snappy23 View Post
    1. Differentiate the following with respect to x
    a.
    y=3/2x2
    b.
    y=ln (x3+x)
    c.
    y=ex/1n(3x)

    can anyone manage this? good luckxx
    Do you mean
    a. y= (3/2)x^2?
    If so, do you know the formula for the derivative of x^n: (x^n)'= nx^(n-1). That's usually one of the first formulas you learn.

    b. y= ln(x^3+ x)?
    Use the fact that the derivative of ln(x) is 1/x and the chain rule.

    c. y= e^x/ln(3x)?
    Use the fact that the derivative of e^x is e^x and the quotient rule.
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  4. #4
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    Quote Originally Posted by skeeter View Post
    1. I'm assuming the function is y = \frac{3}{2x^2}

    rewrite as y = \frac{3}{2}x^{-2} ... now use the power rule for derivatives.

    2. derivative for the log of a function y = \ln(u) ...

    y' = \frac{u'}{u}

    3. y = \frac{e^x}{\ln(3x)} ... use the quotient rule
    For a. i got y=3x/2x2 = 2x-2
    dy/dx = 3x-2x -2 -1 = 6x-3 = 16/x3

    did anyone else?
    i can not do b or c. can anyone help there?
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