f(x)= 5xe^-.2x
Domain of the function = All real numbers
Intercepts: x=0 y=0
Vertical asymptote = none
Horizontal asymptote = y=0
Find f'(x) = 5/.2e^.2x
Let me know if I'm doing anything wrong so far. Thanks, appreciate all help
f(x)= 5xe^-.2x
Domain of the function = All real numbers
Intercepts: x=0 y=0
Vertical asymptote = none
Horizontal asymptote = y=0
Find f'(x) = 5/.2e^.2x
Let me know if I'm doing anything wrong so far. Thanks, appreciate all help