f(x)= 5xe^-.2x
Domain of the function = All real numbers
Intercepts: x=0 y=0
Vertical asymptote = none
Horizontal asymptote = y=0
Find f'(x) = 5/.2e^.2x
Let me know if I'm doing anything wrong so far. Thanks, appreciate all help
f(x)= 5xe^-.2x
Domain of the function = All real numbers
Intercepts: x=0 y=0
Vertical asymptote = none
Horizontal asymptote = y=0
Find f'(x) = 5/.2e^.2x
Let me know if I'm doing anything wrong so far. Thanks, appreciate all help
Everything looks fine except for the derivative.
$\displaystyle f(x) = 5xe^{\frac{-x}{5}} $
$\displaystyle \implies f'(x) = 5e^{\frac{-x}{5}} + 5x\frac{-1}{5}e^{\frac{-x}{5}}$ by the product rule.
It can be simplified further.