Suppose i solved the integral (correctly) and i get as my answer $\displaystyle \arctan({\tan{x}})$ and i want the area from 0 to $\displaystyle \pi$...how do I solve that, what do i do to get around the 0-0?? thanks
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Hello, polymerase! Note that: .$\displaystyle \arctan(\tan x) \:=\:x$ Also that: .$\displaystyle \arctan 0 \:=\:0,\:\pm\pi,\:\pm2\pi,\:\hdots$ What was the original integral? It must have been equivalent to: .$\displaystyle \int 1\,dx$
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