Originally Posted by

**dcfi6052** I was going thorough a horizontal asympototes question and got stuck. This is the queston.

Determine th H.A for the following function. Draw a sketch to show whether the function is above or below the asymptote as x approches infinity.

y=8x2-3/2x2+x-1 , (8x2-3 means 8x squared-3)

I determined that the H.A is y=4, but do not know how to determine if the function is above or below the asymptote as x approches infinity. Can someone explain how to figure this out with an example.