Can someone help with these two questions. Determine the length of the given curve from 0 to from 1 to
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Originally Posted by chengbin Can someone help with these two questions. Determine the length of the given curve from 0 to from 1 to Hi The elementary displacement along a curve is If then Therefore The length of the curve is
Thanks, I know that, but I just can't get the answer in my solution book. So I was hoping someone will write a step by step instruction of solving it.
If you apply the formula for the first one which can be solved by parts
And I don't know how to integrate
Originally Posted by chengbin And I don't know how to integrate try to do so
???
Do you understand it??
OMG, that's the dumbest mistake I've done in a long time. Oh I found out how to integrate it using integration by parts. I'm not sure how your way of doing it works. Anybody help me with the other one? y=lnx
Last edited by chengbin; Mar 28th 2009 at 08:04 PM.
For the first one there is a more simpler way by parts where u = 2x
Originally Posted by running-gag For the first one there is a more simpler way by parts where u = 2x Actually over here in my school, I was advised to remember these formulas Though we were asked to remember it, I never did it, alwas liked the proving stuff, its better , Better to prove it A
Originally Posted by chengbin can anyone help with y=lnx? Even if it takes many posts tell us, No spoon feeding now, learn from first 1) What is f'(x) in this case ? 2) What was written(Formula) in RG's first post 3)How to put 4) how to integrate Show these steps and the place you hanged this time!
Last edited by ADARSH; Mar 29th 2009 at 10:03 AM.
I got y=x^2 now. It was a pain the in butt to do it. I'll just write my steps here to ask if there is a better way. From 0 to Let When x=0, When , Let This is one ugly integral.
Originally Posted by chengbin [snip] Anybody help me with the other one? y=lnx Make the substitution .
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