# Thread: Double Integrals

1. ## Double Integrals

Can anybody help me with this?
See Attachment

Thanks,
Ishan

2. Use $0\le x^2+y^2\le 1$ in your exponent and integrate over the region.

So $1=e^0\le e^{4(x^2+y^2)}\le e^4$

and $\pi=\int\int_D DA \le \int\int_D e^{4(x^2+y^2)}DA\le e^4\int\int_D DA=e^4\pi$