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Math Help - How to find oblique Asymptote

  1. #1
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    How to find oblique Asymptote

    How do you find the oblique asymptote of 2X^2/ X-4
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    Quote Originally Posted by supersaiyan View Post
    How do you find the oblique asymptote of 2X^2/ X-4
    To find oblique (or "slant") asymptotes, do the polynomial long division:

    [html] 2x + 8
    ----------------
    x - 4 ) 2x^2 + 0x + 0
    2x^2 - 8x
    ----------------
    8x + 0
    8x - 32
    ----------------
    32[/html]
    So the slant asymptote will be y = 2x + 8.
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    Thanks, that what I thought but my teacher said it's just 2X
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    Quote Originally Posted by supersaiyan View Post
    Thanks, that what I thought but my teacher said it's just 2X
    Graph the function and look. Does the slant asymptote appear to pass through the origin, or not? (Make sure you "zoom out" on the graph, so you can see what's going on off to the sides. The slanty trend of the curve does not correspond to a line through the origin!)
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  5. #5
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    Quote Originally Posted by supersaiyan View Post
    Thanks, that what I thought but my teacher said it's just 2X
    If the equation is y = \frac{2x^2}{x} - 4 then your teacher is correct.

    If the equation is y = \frac{2x^2}{x - 4} then your teacher is wrong.
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