How do you find the oblique asymptote of 2X^2/ X-4

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- March 27th 2009, 04:40 AMsupersaiyanHow to find oblique Asymptote
How do you find the oblique asymptote of 2X^2/ X-4

- March 27th 2009, 04:48 AMstapel
To find oblique (or "slant")

**asymptotes**, do**the polynomial long division**:

[html] 2x + 8

----------------

x - 4 ) 2x^2 + 0x + 0

2x^2 - 8x

----------------

8x + 0

8x - 32

----------------

32[/html]

So the slant asymptote will be y = 2x + 8. :D - March 27th 2009, 01:24 PMsupersaiyan
Thanks, that what I thought but my teacher said it's just 2X

- March 28th 2009, 10:42 AMstapel
Graph the function and look. Does the slant asymptote appear to pass through the origin, or not? (Make sure you "zoom out" on the graph, so you can see what's going on off to the sides. The slanty trend of the curve does

*not*correspond to a line through the origin!) (Wink) - March 28th 2009, 04:06 PMmr fantastic