How to find oblique Asymptote

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March 27th 2009, 04:40 AM
supersaiyan

How to find oblique Asymptote

How do you find the oblique asymptote of 2X^2/ X-4
March 27th 2009, 04:48 AM
stapel

Quote:

Originally Posted by supersaiyan

How do you find the oblique asymptote of 2X^2/ X-4

To find oblique (or "slant") asymptotes, do the polynomial long division:

[html] 2x + 8
----------------
x - 4 ) 2x^2 + 0x + 0
2x^2 - 8x
----------------
8x + 0
8x - 32
----------------
32[/html]
So the slant asymptote will be y = 2x + 8. :D
March 27th 2009, 01:24 PM
supersaiyan

Thanks, that what I thought but my teacher said it's just 2X
March 28th 2009, 10:42 AM
stapel

Quote:

Originally Posted by supersaiyan

Thanks, that what I thought but my teacher said it's just 2X

Graph the function and look. Does the slant asymptote appear to pass through the origin, or not? (Make sure you "zoom out" on the graph, so you can see what's going on off to the sides. The slanty trend of the curve does not correspond to a line through the origin!) (Wink)
March 28th 2009, 04:06 PM
mr fantastic

Quote:

Originally Posted by supersaiyan

Thanks, that what I thought but my teacher said it's just 2X

If the equation is $y = \frac{2x^2}{x} - 4$ then your teacher is correct.

If the equation is $y = \frac{2x^2}{x - 4}$ then your teacher is wrong.

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