For 4.95 seconds, a particle moves in a straight line according to the position function:
f(t) = (e^(t)) (5 - t) -5
Find the velocity of the particle at t = 0, t = 1.
Okay the book states "the velocity function is the derivative of the position function. So I'm assuming I have to take the derivative of the function f(t)?
Now I need to find when the particle is at rest.
Okay, so the particle will be at rest when the velocity is zero right? v(t)=0
The velocity function I have is (e^(t)) * (4 - t)
So if I set this up like this:
(e^(t)) * (4 - t) = 0
and then solve for "t" I should get when the particle is resting?